If you only want a repeated character to print out once, add another set to keep track of letters which have already been printed. This is another way to solve it.. Scanner s = new Scanner(System.in); Converting string's characters to arraylist using streams. How did this hand from the 2008 WSOP eliminate Scott Montgomery? How can I print a character multiple times in a single line? I see no example of this method in the. Use one more set to store the duplicate element and print the element. So basically, if the input string is this: String s = "House, House, House, Dog, Dog, Dog, Dog"; I need to create a new string list without repetitions and save somewhere else the amount of repetitions for each word, like such: New String: "House, Copyright 2023 @ Is It Actually | Hand Crafted By Vrashi. What is the smallest audience for a communication that has been deemed capable of defamation? * Java Program to find duplicate characters in String. Only duplicates we need to print. Repeat a string in JavaScript a number of times. Firstly, we take the input of String. Could ChatGPT etcetera undermine community by making statements less significant for us? Replacing TreeMap with LinkedHashMap will print the repeated character in the same order they appear in given input. Finally, collect characters and its count using Java 8 Collectors. It's not entirely clear to me what's required by "using only the Set interface" but I'll assume that this means that the duplicate characters are to be returned in a Set. @Anonymous, It actually does print 'a' twice for 'Java', its just that I missed when I copied output from Eclipse. 5 Answers. Thanks "Anonymous", very helpful stuff for searching with minimal resources. here you go: Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. Approach: Create a count array to store the frequency of each character in the given string str.Traverse the string str again and check whether the frequency of that character is 0 or not. Input : "aaabbccd" Output : "abcd" Explanation. So at the end of outer for loop we will be getting all the duplicate elemntsfrom given string. Now, iterate through the string to compare each character with rest of the string. The outer for loop will be pointing the first element, second for loop will iterate through all other elements if there is any match between the current elemnt then increase the count by 1. Could ChatGPT etcetera undermine community by making statements less significant for us? 16. Extract words from string using split () method and store them in an array. Convert String in char array and append it to String builder and check if String builder Already contains that char then print that duplicate char. Why is the 'a' of Java not occuring twice? Anybody knows how to find and remove duplicate words in as string with concept of hashtable and string tokenizer, Hello @Anonyous, check these tutorials, you may get some idea how to remove duplicate characters from stringand How to find duplicate words in Java String, My version of code#includeusing namespace std;int main(){ string str; getline(cin,str); for(int i=0;i='A'&&s[i]<='Z') cnt[s[i]-'A']++; } for(i=0;i<26;i++) { if(cnt[i]>1) printf("%c :%d\n",i+'a',cnt[i]); } return 0;}, S="String with duplicates";p=S.charAt(0);for(i=1;i> s; p=s; while (strlen(p)>0) { strncpy_s(s_, p, 1); strncpy_s(s1, s, strlen(s)-strlen(p)); if(strrchr(p, *p)!=strchr(p, *p) && strchr((p+strcspn(p, s_)+1), *p)==strrchr(p, *p) && strcspn(s1, s_)==strlen(s1) ) cout << *p << ": " << 2 << endl; p++; }system("pause");}, import java.util.Scanner;public class DuplicateString { public static void main(String[] args) { Scanner sc = new Scanner(System.in); char[] str = sc.next().toLowerCase().toCharArray(); int[] charArray = new int[26]; for (int i = 0; i < str.length; i++) { charArray[Math.abs(97-str[i])]++; } for (int i = 0; i < charArray.length; i++) { if (charArray[i] > 1) { System.out.printf("%c",Math.abs(97+i)); System.out.println(); } } }}, #include 2#include 3#include 4#include 56int main() {7 char a[10];8 int i,j,has[1000]={0},l;9 scanf("%s",a);10 l=strlen(a);11 for(i=0;i1)17 {18 printf("%c -> %d\n",i+65,has[i]);19 }20 }21 22}23, private static void characterCount(String str) { HashMap charCountMap = new HashMap<>(); for (Character ch : str.toLowerCase().toString().toCharArray()) { Integer count = charCountMap.putIfAbsent(ch, 1); if (null != count) { charCountMap.put(ch, charCountMap.get(ch) + 1); } } Map charMap = charCountMap.entrySet().stream().filter(map -> map.getValue() != 1).collect(Collectors.toMap(p -> p.getKey(), p -> p.getValue())); System.out.println(charMap); }, public class RemoveDuplicatesFromString { public static void main(String[] args) { String input = "hello world"; String output = removeDuplicates(input); System.out.println(output); } private static String removeDuplicates(String input) { HashSet mySet = new HashSet(); String output=""; for(Character c :input.trim().replaceAll(" ", "").toCharArray()) { if(mySet.add(c)==false) if(!output.contains(c+"")) output = output+c; } return output; }}, import java.util.Scanner;public class JavaApplication19 { public static void main(String[] args) { Scanner sc=new Scanner(System.in); System.out.println("Program to print repeated characters in a string"); System.out.println("Enter the string"); String s1=sc.next(); System.out.println("Repeated characters in the given string is:"); for(int i=0;i=2){ System.out.print(s1.charAt(i)); } } } } System.out.println(); }}, import java.util.Scanner;public class JavaApplication19 { public static void main(String[] args) { Scanner sc=new Scanner(System.in); System.out.println("Program to print repeated characters in a string"); System.out.println("Enter the string"); String s1=sc.next(); String s2=""; int flag=0; for(int i=0;i=2){ flag=1; s2=s2+String.valueOf(s1.charAt(i)); } } } } if(flag==1){ System.out.println("Repeated characters in the given string is:"); System.out.println(s2); }else{ System.out.print("NULL"); } System.out.println(); }}, import java.util.List;import java.util.ArrayList;import java.util.Scanner;public class S5 {static int k=0,val=0; public static void main(String[] args) { Scanner sc = new Scanner(System.in); String s1=sc.next(); int count=0; String otherString=""; List l1= new ArrayList(); for( char i='a';i<='z';i++){ count = s1.length()-s1.replaceAll( String.valueOf(i) ,"").length(); // System.out.println(count); if(count>1){ String character = ""+i; otherString = otherString.concat(character); l1.add(count); } } char[] ch=otherString.toCharArray(); int[] ret = new int[l1.size()]; int j = 0; for (Integer e : l1) ret[j++] = e.intValue(); for(int i=0;i charMap = new HashMap (); "); getch(); return; } int nLen = strlen(input); if(nLen <= 1) { printf("Invalid String!!! I have to make a program that reads a number, and So overall time complexity of above solution is O(n 3). Iterate through each word in a sentence and increment the count of that word by 1. I am new to Java. Using HashSet. This means I cannot use a loop. Java String: Exercise-110 with Solution. *;import java.lang. Now, in the main() method, declare and initialize strings and a positive integer k. Then, call the user-defined method using string and k as arguments. Following program demonstrate it. If you want to print something multiple times, then the easiest way (not necessarily the best way, but this is homework after all) is to put it in a Maximum difference between frequency of two elements such that element having greater frequency is also greater. Powered by. Example2: Let the given string be Dattatrey patil. Instead of clumsy solutions above, just loop the string once from left to right so to speak and at every character check if it also exists on the right hand side yet left to loop. For example: "Tigers (plural) are a wild animal (singular)". "Fleischessende" in German news - Meat-eating people? Another way to remove repeated characters from a string is through the use of a Set. import java.util. @artsArt, yes, you can use recursion, no problem with that, but your solution will only print the duplicate characters, not their count. WebHow do you find duplicate characters in a string? In the above input z and a are repeating twice. Is this mold/mildew? * Find all duplicate characters in a String and print each of them. For every character, check if it repeats or not. All Non-repeating character in a given string is: p y h o s r i g. Most Recommend Questions :-. publi Use whatever you need, it only depends on your real requirements, but one If value of Char is more than 1, that means it Java: Only Print Unique Characters in a String. Your email address will not be published. If you can use a third-party library, the following will work using Eclipse Collections : String str = "india"; "Fleischessende" in German news - Meat-eating people? 1.1 Steps for counting repeated character occurrences : Create empty HashMap of type Character & Integer. Thanks for contributing an answer to Stack Overflow! Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide, The future of collective knowledge sharing. 2.4. rev2023.7.24.43543. they are least repeating characters and z is repeating first, so i want to get z as an output. Initialize two variables, say max, charMax to store the frequency of maximum repeating character and the maximum repeating character respectively.